3[z-(6z+15)+5]=3(z+2)

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Solution for 3[z-(6z+15)+5]=3(z+2) equation:


Simplifying
3[z + -1(6z + 15) + 5] = 3(z + 2)

Reorder the terms:
3[z + -1(15 + 6z) + 5] = 3(z + 2)
3[z + (15 * -1 + 6z * -1) + 5] = 3(z + 2)
3[z + (-15 + -6z) + 5] = 3(z + 2)

Reorder the terms:
3[-15 + 5 + z + -6z] = 3(z + 2)

Combine like terms: -15 + 5 = -10
3[-10 + z + -6z] = 3(z + 2)

Combine like terms: z + -6z = -5z
3[-10 + -5z] = 3(z + 2)
[-10 * 3 + -5z * 3] = 3(z + 2)
[-30 + -15z] = 3(z + 2)

Reorder the terms:
-30 + -15z = 3(2 + z)
-30 + -15z = (2 * 3 + z * 3)
-30 + -15z = (6 + 3z)

Solving
-30 + -15z = 6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-30 + -15z + -3z = 6 + 3z + -3z

Combine like terms: -15z + -3z = -18z
-30 + -18z = 6 + 3z + -3z

Combine like terms: 3z + -3z = 0
-30 + -18z = 6 + 0
-30 + -18z = 6

Add '30' to each side of the equation.
-30 + 30 + -18z = 6 + 30

Combine like terms: -30 + 30 = 0
0 + -18z = 6 + 30
-18z = 6 + 30

Combine like terms: 6 + 30 = 36
-18z = 36

Divide each side by '-18'.
z = -2

Simplifying
z = -2

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